This is exact quote from cj1965 post: In theory, half the voltage applied to a driver will result in half the sound pressure in the output (-3db). |
Thanks, Kijanki. Here's another interesting quote, this one from the thread Tim referred to above:
CJ1965 4-19-2018 For some people, "results" means using antiquated 80 year old technology
that is highly vulnerable to changes in performance depending on what
it's connected to. And for some folks, the lack of bass and exaggerated
highs, coupled with increased harmonic distortion when using this
ancient "technology" is "pleasing" or "desirable". Similarly, others see
the pops and ticks, rapid wear, uneven high frequency performance,
limited dynamic range, increased distortion, wow, and flutter associated
with ancient vinyl technology as "more authentic". Unfortunately, we
can't confine such individuals who promote and buy this junk to padded
cells. We pretty much have to create invisible "padded cells" that
effectively allow ourselves to ignore them.
Best regards, -- Al |
This is exact quote from cj1965 post:
In theory, half the voltage applied to a driver will result in half the sound pressure in the output (-3db). Res ipsa loquitur, huh? Obviously he didn't actually do the math, but based this on belief instead- the exact thing of which he was accusing others... |
For a single driver : The change in dB in input voltage is equal to the change in output SPL in dB. Voltage dB can be calculated in this fashion: dB = 20 x log ( Vnew / Vold ) in the case of half the voltage: 20 x log ( 1 / 2 ) ~= (- 6 dB) Also, you can use this handy web gizmo: http://www.sengpielaudio.com/calculator-gainloss.htm |
Also, we are so far from the OP's original topic, maybe we should let this thread just die. :) |