Yeah I guess I just have to roll with it, the rule of thumb as a guide along with the formula + testing by ear.
However, applying the rule becomes tricky since the data spec quotations on several transformers are not quoted at 47,000. For example:
1.Cinemag 3440AHPC has.....37.5 or 150 : 50K
2. Another RCA has..... 600 or 150: 15K
For the above trafos do I have to adjust the calculations since they are not into 47,000 ohms, one is into 50K and the other is into 15K, to find the effective load?
To find the turns ratios please tell me if this is correct:
1. 50,000/x^2 = 37.5 solve x-> implies x=36.5 turns ratio
then to find impedance do I standardize to 47,000 in the following way?
47,000/36.5^2 -> 35 Ohms ?
I will repaeat the logic for the second cartridge as well which using the 150 tap with the quotation value 15K.
2. 15,000/x^2 = 150 solve x-> implies x = 10 turns ratio
then to find impedance 47,000/10^2 -> 470 ohms
My point is most transformers out there are not quoted into 47,000 ohms like the phono section is, they are often 50,000 or even 15,000. So if using those quotations, do you not have to solve for the turns ratio with their quotation values first, then use 47,000/turns^2 to find the effective load ?
If you look at the above example 2. it is quoted at
"600, 150: 15K"...so using the 150 tap I get a turns ratio of 10, and this provides and effective load @ 47,000 of 470 and not 150 the way it was quoted.
Then once this is done which set of turns ratios and effective impedances to I put into equation (*) to find the voltage?
However, applying the rule becomes tricky since the data spec quotations on several transformers are not quoted at 47,000. For example:
1.Cinemag 3440AHPC has.....37.5 or 150 : 50K
2. Another RCA has..... 600 or 150: 15K
For the above trafos do I have to adjust the calculations since they are not into 47,000 ohms, one is into 50K and the other is into 15K, to find the effective load?
To find the turns ratios please tell me if this is correct:
1. 50,000/x^2 = 37.5 solve x-> implies x=36.5 turns ratio
then to find impedance do I standardize to 47,000 in the following way?
47,000/36.5^2 -> 35 Ohms ?
I will repaeat the logic for the second cartridge as well which using the 150 tap with the quotation value 15K.
2. 15,000/x^2 = 150 solve x-> implies x = 10 turns ratio
then to find impedance 47,000/10^2 -> 470 ohms
My point is most transformers out there are not quoted into 47,000 ohms like the phono section is, they are often 50,000 or even 15,000. So if using those quotations, do you not have to solve for the turns ratio with their quotation values first, then use 47,000/turns^2 to find the effective load ?
If you look at the above example 2. it is quoted at
"600, 150: 15K"...so using the 150 tap I get a turns ratio of 10, and this provides and effective load @ 47,000 of 470 and not 150 the way it was quoted.
Then once this is done which set of turns ratios and effective impedances to I put into equation (*) to find the voltage?