@atmasphere
You’re using the wrong formula - equating electrical power to sound power. The db formula for sound power is :
10 X log 10 (P/Po) db
where P is the measured sound power and Po is the reference level.
If you doubt me, look it up. I believe it’s spelled out pretty clearly in Wikipedia.
And sound power is a function of the force applied, (in this case the voltage) along with the area and displacement over which that force is applied. When you halve the force and double the area, you wind up with roughly the same sound power that you began with. But improved acoustical coupling with increased area improves net efficiency (electrical power in versus sound power out).
You’re using the wrong formula - equating electrical power to sound power. The db formula for sound power is :
10 X log 10 (P/Po) db
where P is the measured sound power and Po is the reference level.
If you doubt me, look it up. I believe it’s spelled out pretty clearly in Wikipedia.
And sound power is a function of the force applied, (in this case the voltage) along with the area and displacement over which that force is applied. When you halve the force and double the area, you wind up with roughly the same sound power that you began with. But improved acoustical coupling with increased area improves net efficiency (electrical power in versus sound power out).