Before anybody goes off the deep end, I'm simply applying these formulas to power cords, and nothing else. That flakey AC coming out of the wall hasn't changed, and a power cord is not going to change it. A heavy gauge power cord with good connectors on both ends is going to work as well as any according to these laws. Now give me your "snake oil" explanation as to why yours is better than mine.
P = power (Watts)
V = voltage (Volts)
I = current (Amperes)
R = resistance (Ohms)
Electric Current Formulas
I = V / R (2a)
I = P / V (2b)
I = (P / R)1/2 (2c)
Electric Resistance Formulas
R = V / I (3a)
R = V2/ P (3b)
R = P / I2 (3c)
Electrical Potential Formulas - Ohms Law
Ohms law can be expressed as:
V = R I (4a)
V = P / I (4b)
V = (P R)1/2 (4c)
Example - Ohm's law
A 12 volt battery supplies power to a resistance of 18 ohms.
I = 12 (Volts) / 18 (ohms)
= 0.67 (Ampere)
P = power (Watts)
V = voltage (Volts)
I = current (Amperes)
R = resistance (Ohms)
Electric Current Formulas
I = V / R (2a)
I = P / V (2b)
I = (P / R)1/2 (2c)
Electric Resistance Formulas
R = V / I (3a)
R = V2/ P (3b)
R = P / I2 (3c)
Electrical Potential Formulas - Ohms Law
Ohms law can be expressed as:
V = R I (4a)
V = P / I (4b)
V = (P R)1/2 (4c)
Example - Ohm's law
A 12 volt battery supplies power to a resistance of 18 ohms.
I = 12 (Volts) / 18 (ohms)
= 0.67 (Ampere)