Hi Scott,
"o/p" presumably means "output." If 2 mv in results in 0.5 V out, since 0.5 V = 500 mv the gain is 500/2 = 250x (i.e., 250 times).
The ratio of two voltages expressed in db equals 20 times the logarithm of the ratio. So 250x is a gain of:
20 x log(250) = 48 db
Best regards,
-- Al
"o/p" presumably means "output." If 2 mv in results in 0.5 V out, since 0.5 V = 500 mv the gain is 500/2 = 250x (i.e., 250 times).
The ratio of two voltages expressed in db equals 20 times the logarithm of the ratio. So 250x is a gain of:
20 x log(250) = 48 db
Best regards,
-- Al

