Resistor in phono stage

What do you mean by "wrong resistor"?
What cartridge(s) are you using, and by what criterion do you think the load resistor is wrong?  If you have an ohmmeter, just stick one probe into the RCA phono input jack and place the other probe on the outer barrel of the RCA jack; the resistance thus measured will be the value of the load resistor, unless there is a SUT in the signal path.  I don't know what the value should be for the PH3se.  The standard for MM cartridges is 47K ohms.  MC cartridges typically are run with more of a load (meaning a lower value of load resistance, down to around 100 ohms in some cases).  

The ARC PH3SE in a MM only phono stage.  It has a factory set fixed output of 54db gain, 47Kohm impedance and 90pF of capacitance.

You can change only the capacitance by soldering in different values of resistors.  I would make sure if this has even been done.  I have owned several of the PH3 and PH3SE units and none of them had ever had a resistor soldered in.

Here is an excellent white paper on loading:

http://www.hagtech.com/loading.html

Mofi, baby.  Thanks for the info on the PH3SE. Of course you CAN change the 47K load resistor by directly de-soldering it, removing it from the circuit, and replacing it with another resistor of preferred value.  Many listeners prefer a 100K load resistor for most MM cartridges. (See the thread on MM cartridges.)  Anyway, I think you must have misspoke by suggesting you can change capacitance by changing the load resistor. No problemo.

Certainly, 47K cannot be regarded as the "wrong" resistor for an MM. We now need to know what cartridge the OP is using and whether he is using a SUT between the phono and the cartridge. Etc.

Page 2 of the PH3 owner's manual talks about changing Input Impedance and Input Capacitance:

http://www.audioresearch.com/ContentsFiles/PH3%20manual.pdf

Thanks, mofi. What I see is a description of how to wire resistors (and/or capacitors) so they end up in parallel with the input, which will effectively lower the input resistance (and/or raise the input capacitance).  Thus, the end user can achieve nearly any resistance desired, below 47K. (Resistors wired in parallel will always result in a net value lower than that of the highest value of any one of the resistors.)  Adding a capacitor in parallel, using those same binding posts provided, will raise the total capacitance, since capacitors in parallel are additive in value.  (Pardon me if you already know this.)

But meantime, the OP seems to have lost interest in his own question. Which is fine.