Another Cable Burn-in Question


I've checked the archives and I'm still not certain about this. I want to burn-in a new ic cable between CD player and preamp. I set the CD player to repeat/play but does the preamp need to be turned on? I'd rather not leave my tubed pre on during burn-in if I don't have to.
jc4659
As Rodman states, the preamp doesn't need to be on, I've burned in tons of cables, capacitors this way. Get a real cheapo cd player for the burn in, $100 or less, good investment for further burns.
I must be missing sojmething or electron flow theory has significantly changed in the recent past somehow.

Just how is the current/voltage being allowed to return to the source component if the downstream preamp is not powered up?

I am thinking the circuit would be open in that event and no signal, voltage, or current will be conducted in an open circuit. Neither would one be passed in a shorted ckt which could also be the deal without power to the secondary component, again, allowing the signal to return to the source.

???
I must be missing sojmething or electron flow theory has significantly changed in the recent past somehow.

Just how is the current/voltage being allowed to return to the source component if the downstream preamp is not powered up?

Simple. You just place the preamp below the source - that way the heavy bass can slide down the interconnects easily.
If you look at the manual for your preamp, the section dealing with source connections generally is titled, "INPUTS". That's because the signal voltage(and it's swings) are coming FROM the source to the pre. The input impedance of the pre remains the same and completes the circuit for the source's interconnects, whether the unit is turned on or not, because there are PASSIVE components(attenuator/resistor/etc) in any preamp's input circuitry that present a load for them. The only signal that LEAVES the preamp, does so from the OUTPUTS. To burn interconnects between a pre and power amp: The amp(likewise) need not be powered up for exactly the same reasons(passive components at the inputs), while a source and the pre would(to provide signal voltage TO the interconnects).