Another Cable Burn-in Question

A passive component(in this case generally an attenuator) does not change it's impedance value when the equipment in which it's installed is turned either on or off. The CDP or DAC output will never see a "virtually open circuit". Just put an ohmeter across the input of a preamp while turned off to verify.

I absolutely agree! I thought of this after I posted; "how about passive pre-amps?" I think the current would flow through the interconnect into the pre-amp.

Thanks for pointing that out!

why use a cd player when you can use a fry baby by hagerman ?

Mrtennis

given these posts and assumptions why bother to do anything other than connect the cables and allow their differing potentials and impeadances to burn them in.... BTW... Do you have to plug the hagerman thingy into an AC power supply?

Imagine that. I'd think Mr. hagerman would be all over this cable burn in biz, huh? Why do you suppose he uses electricity to generate a signal with sufficient values to run in cables, instead of the static approach previously mentioned?

here's a thought... let's have a race. Two folks buy the same cables. one pair each. one goes the static route by merely leaving them plugged into a nonoperational componenet, and the other goes the archaine path of actually turning the components on and sending a signal thru the cables. At the end of 10 days another third party will listen to each cable pair, static and regular, not knowing which is which and report back. thereafter, each of the ones directly involved can try them... again not knowing which or how they were run in.

I'd bet money, in a honest examination, there will be easily descernable diffs... with the hot pair being the more amenable ones.

Good idea? Bad Idea?

the suggestion to use a break-in device is based upon the idea of not hastening the demise of a laser mechanism.

a tuner or other low current source is suitable as well.

i agree that using a break-in device as compared to say a cd player will initially produce contrasting sonic differences. i suspect, after some duration, one won't be able to distinguish one pair from another. however, i'm not sure of the duration of a signal passed through an interconnect cable, neede to erase initial sonic differences.