RCA to XLR adapters?


I currently have a complete single end (RCA) input system but was possibly looking at other amps that are fully balanced and accept only balanced or XLR connections. My question is will these adaptors give you the full benefit of a balanced amp or preamp? Or will it simply was work ok? I have expensive cable that I will not replace but is terminated with RCA's.
bobheinatz
Won't these advantages be negated if a single-ended signal is put through a balanced amp?

No. As soon as the signal is in the amp, it will be in the balanced domain if the amp is really balanced.

Using a Jensen may not be a bad idea- you have the SE preamp drive the Jensen, and then run you balanced interconnect as far as you need to the amp. I've done that a lot and its always worked well.
As soon as the signal is in the amp, it will be in the balanced domain if the amp is really balanced.
But if one side of the balanced signal path is processing a music signal, and the other side is processing 0 volts (as opposed to a signal that is the inverse of what is being processed by the other side), how will any distortion products be cancelled, and how will the load on the power supply not fluctuate with the music (assuming the amp is not Class A)?

I'm not disagreeing, just questioning something that doesn't seem to make sense to me.

Best regards,
-- Al
Thinking a little further about my previous post, Ralph's point does indeed make perfect sense to me, assuming that the input stage within the amp is what is known as a long-tailed pair differential amplifier. That will produce a balanced output in response to a single-ended input, thereby realizing the benefits of fully balanced internal design in the subsequent stages of the amplifier, including the power stages where it matters most.

I assume that is the architecture used in Ralph's designs. So the question becomes whether or not the input stage of all or at least most other "fully balanced" amps can be expected to have been designed in an equivalent manner. I don't know the answer to that question.

Best regards,
-- Al