Paperw8, let me supplement the reference I previously provided with this one, supporting my contention that db = 20log(V1/V2), rather than 10log(V1/V2) as you have claimed. It was written by someone possessing technical credentials that are utterly impeccable. See his biographical information here.
With respect to your related erroneous contention, that first order filters roll off at 3db/octave, I suggest that you Google the terms "first order filter" and "6 db per octave," placing both phrases within the search term field, with the quotes. You will find countless references supporting the 6db figure.
If after viewing all of that, as well as the reference I previously provided, you find yourself continuing to insist that db = 10log(V1/V2) and that first order filters roll off at 3db per octave, I will have no further comment.
Regards,
-- Al
With respect to your related erroneous contention, that first order filters roll off at 3db/octave, I suggest that you Google the terms "first order filter" and "6 db per octave," placing both phrases within the search term field, with the quotes. You will find countless references supporting the 6db figure.
If after viewing all of that, as well as the reference I previously provided, you find yourself continuing to insist that db = 10log(V1/V2) and that first order filters roll off at 3db per octave, I will have no further comment.
Regards,
-- Al

