AC Power Cord Wire Gauge


I guess this is a two-fold question dealing with the amount of AC power flowing through normal - that is, not special 20 amp dedicated lines - 15 amp house circuits. I'm guessing that these lines use 14 gauge wire, with a 15 amp breaker, to say a duplex receptacle. One conversion I read is that 15 amps X 120 = 1,800 watts. So, the first question is: If you plug a surge protector/power strip/power conditioner into one outlet in the duplex receptacle and then plug, say, four audio components into that "power strip" can they draw the full complement of AC power available (i.e., the power isn't split between the two outlets in the receptacle)? If you plug another component into the other outlet does it reduce the power available to the "power strip"?

Second, if the house wiring to the duplex receptacle is 14 gauge from the electrical panel, does it make any difference if you buy heavier (say a 10 gauge) after-market audiophile power cords for the audio components? Or, would a 14 gauge cord - the same gauge as the house wiring - be sufficient? Can a 10 gauge cord flow more power than is available through the house wiring at 14 gauge?

Thanks.
kencalgary
You can see by the statement you quoted that I am not scientific enough to posit an intelligent response ...

On the contrary, I sincerely felt that your entire response was quite intelligent. In that particular part of it, you were simply citing what you believe some others believe, and I have no doubt that is true (that some others have that belief). I was just saying that that belief that others may have is, in my opinion, not correct!

All the best,
-- Al
The national electrical code requires minimum AWG 12 for 15A circuits.

If you're going to put in new ded. cts, for your audio, and the receptacles will be more than 20 feet from the panel, i recommend going up to AWG 10 to make up for slight voltage drop as the runs get longer.

Tvad, you're not imagining things. The age-old question, "Why make PC's any bigger gauge than what's in the wall?" has a very simple answer: 'energy transfer' I'll explain:
When you plug your whatever into a wall receptacle, you are basically hooking it up (in parallel with other devices plugged into that same 'branch' circuit) across two buss wires (hot and neutral) coming from the panel. Think of this buss (usually a long length of Rom-ex in the wall) as a reservoir of water that under most conditions can never be emptied. Think of the power cord as a pair of tubes (hot conductor and neutral conductor) that you stick into this reservoir. Now water can flow (current) into one conductor, through the whatever, and back out the other conductor (and this process reverses 60 times a second because the current alternates.)

If the water is flowing through an amplifier, it's doing quite a bit of work, but in just a sixtieth of a second, it has to get back to the reservoir and then reverse direction! Sounds like an electron traffic jam waiting to turn into gridlock! To insure this doesn't occur, you provide many many lanes (or in this case, large conductors) and you lay them out so drivers aren't blinded by oncoming headlights (inductance and capacitance) slowing things down unnecessarily ;-) Simply put, the energy transfer requirements, back and forth between the device and the reservoir, are quite different in nature than what it takes to keep the reservoir full.

Devices requiring less power (preamps, tuners) can transfer current back and forth through smaller conductors without "impediments" arising -- with one bizarre exception: DACs! (or any device with a D/A or A/D chip in it.) Don't ask me why, I don't know, but they benefit from big AC conductors also (but probably for different reasons than amps.)

.
Let's do the math.

Take a stereo 100 W/ch amplifier, running in class A at 40% efficiency. That adds up to 500W draw. Much less than the 14Ga, 115V*15A=1725W capacity of the house circuit. Class A/B is more efficient and will draw varying current although most peak demand is supplied through power supply capacitors. Class D at twice the efficiency as class A, even if it had no capacitive reserve, would still be capable of 1725*80% = 690 W/ch (stereo) peaks.

Unfortunately, real life doesn't work so simply and I typically suggest not exceeding 50% the rating on most electrical for audio, if possible.

Consider, just for fun. my current system capable of drawing over 4000W and the electrical requirements.
The age-old question, "Why make PC's any bigger gauge than what's in the wall?" has a very simple answer: 'energy transfer' I'll explain:
When you plug your whatever into a wall receptacle, you are basically hooking it up (in parallel with other devices plugged into that same 'branch' circuit) across two buss wires (hot and neutral) coming from the panel. Think of this buss (usually a long length of Rom-ex in the wall) as a reservoir of water that under most conditions can never be emptied. Think of the power cord as a pair of tubes (hot conductor and neutral conductor) that you stick into this reservoir. Now water can flow (current) into one conductor, through the whatever, and back out the other conductor (and this process reverses 60 times a second because the current alternates.)

If the water is flowing through an amplifier, it's doing quite a bit of work, but in just a sixtieth of a second, it has to get back to the reservoir and then reverse direction! Sounds like an electron traffic jam waiting to turn into gridlock! To insure this doesn't occur, you provide many many lanes (or in this case, large conductors) and you lay them out so drivers aren't blinded by oncoming headlights (inductance and capacitance) slowing things down unnecessarily ;-) Simply put, the energy transfer requirements, back and forth between the device and the reservoir, are quite different in nature than what it takes to keep the reservoir full.

At the risk of starting an ecclesiastical controversy (which I hope will not occur), I must respectfully but completely disagree, because as an electrical engineer I believe the quoted perspective would be severely misleading to the original poster and to others who may read this.

Simply put, there is no basis whatsoever in science or engineering for viewing the ac outlet as a point of demarcation between a reservoir, and a set of tubes or whatever that draws water (or in this case current and power) from the reservoir.

The wiring system is just that, a system. Energy is being transferred back and forth at a 60Hz frequency through the house wiring just as much as through the power cord. Increased resistance in the house wiring, due to smaller gauge or greater length, will produce a voltage loss just as readily as in the power cord. And in fact most likely to an even greater degree (since the combined current draws of multiple devices are likely to be flowing through it, rather than the current draw of just one device, and voltage drop equals current times resistance).

As I said earlier, there may be subtle reasons why subtle sonic differences may result when 10 gauge power cords are hooked into 12 gauge house wiring, but the differences are not due to the gauge per se.

Regards,
-- Al
Al -- your explanation represents sound engineering, and I know it well; in fact some embrace those principals to the point of hardwiring their amps' power supply right back to the panel, convinced that strategy will provide the very best energy transfer. Good for them;-)

A real scientist would not be so sure. The facts are a little different than you imply:
As I said earlier, there may be subtle reasons why subtle sonic differences may result when 10 gauge power cords are hooked into 12 gauge house wiring, but the differences are not due to the gauge per se.
First, the difference is NOT subtle (you should try it ;-)
Second, the effect of using larger (and larger!) gauge conductors is the same, regardless of the brand or topology of the cord -- the sonics of the amp will "open up" dramatically! In my own experiments, this improvement continued incrementally up to 8 AWG which is as far as I went, but PS Audio (I think) makes 6AWG PC's, which might make sense to some ;-)

So, counterintuitive or not, it IS the gauge. Why? Well maybe Quantum physics will explain it one day ;-) I'm certainly willing to accept my own explanation as flawed (from an ENGINEERING standpoint) but it's the best I can conjure until science discovers the REAL reason. It's just a matter of time, I'm sure.
.