How does music "move" down a wire?


Please excuse me for this question if it is dumb. I'm trying to understand how music/sound moves down a wire. (I think) I understand how sound is transmitted through air and that an electrical signal is produced by the source (e.g., stylus in groove) which, after various amplification stages, then 'excites' electrons in the speaker cable.

However, I don't know if different notes (e.g., double bass versus flute) 'excite' the electrons in different ways. That is, do the electrons excited by bass notes move slower than those excited by flute notes? To add complication, music is comprised of many notes played at the same time. Do some electrons move with the bass notes and others with the flute notes, or is it a wave of electrons with various layers of frequency one atop the other?

Would electrons be moving similarly in each wire of a stranded cable (i.e., they would only be excited within the boundaries of that particular wire) as opposed to the electrons moving across the full diameter of the cable?
kencalgary
That was a very helpful explaination(s).

"But the signal all gets to the end of the wire at basically the same time"

This makes me think, how different would wire lengths have to be for the acute listener to notice a difference in the arrival time in a pair of a stereo signals at the speakers? Answers based on complex theoretical calulations, general principles or SWAGs all entertained here.
Excellent answers by Elizabeth!
How different would wire lengths have to be for the acute listener to notice a difference in the arrival time in a pair of a stereo signals at the speakers?
Several miles or more, by which point timing differences would of course have long since been swamped by other effects (frequency-dependent signal losses caused by resistance, inductance, capacitance, among many other effects).

Electrical signals (as opposed to individual electrons, whose movement is irrelevant to the question) propagate through wires at roughly 60% to 90% of the speed of light in a vacuum, which in turn is about 186,000 miles per second. If we assume 75% as being typical (the actual number depends mainly on the dielectric constant of the cable's insulation), the corresponding propagation time is about 1.36 nanoseconds per foot of cable. 1.36 nanoseconds is 0.00000000136 seconds.

The speed of sound in room temperature dry air is approximately 1126 feet per second.

Based on the 1.36 ns/foot figure, a 20 foot difference in cable length between the two channels, for example, would result in an arrival time difference at the speakers of 27.2 ns.

Based on the 1126 ft/sec figure for the speed of sound in air, 27.2 ns corresponds to the arrival time difference at the listener's ears that would result from his or her head being 0.00037 inches closer to one speaker than to the other. In other words, not likely to be audible!

Regards,
-- Al
Thanks Elizabeth, that was a great explanation. From your explanation I would guess that connections (e.g., spades) also would affect the wave especially if the connector was a huge hunk of different material? I assume material "density" (or resistance) would impede some frequencies more than others?
Thanks Al, very cool logic. Your analysis would of course hold best in scenario of an anechoic chamber. In the average listening room, reflections and nodes etc. would further diminish any vanishing differences in sound imparted by differences in speaker wire length.

I have fretted about this in certain applications in the past and it has cost me in wasted lengths of speaker wire. I haven't ever noticed a difference in sound with differential lengths of wire, but since I was fretting about everything else, I thought I should worry about this too. Apparently not. Thanks again for your analysis.