That is not exactly correct. The formula is XL = 6.28 x F x L, so you can see that the impedance of an inductor drops with frequency. So they become a dead short at low frequencies. So the frequency where the inductor has an impact is F = (6.28 x L)/XL Consequently, the last thing you want to do is stick an inductive speaker cable in series with another inductor. That low impedance will cause a roll off to occur much sooner. To lower the inductance of a cable, you raise the capacitance.
Likewise, it is a similar situation for electrostatic speakers, except here you want inductive speaker cables because at low frequencies, that cap load looks like an open circuit. This renders the inductance harmless. If you use capacitive cables with electrostatics, they start shunting current away from the speaker, so the speaker never sees those signals.
Hope this helps - I tried to keep it simple and not use any calculus to explain it.
Likewise, it is a similar situation for electrostatic speakers, except here you want inductive speaker cables because at low frequencies, that cap load looks like an open circuit. This renders the inductance harmless. If you use capacitive cables with electrostatics, they start shunting current away from the speaker, so the speaker never sees those signals.
Hope this helps - I tried to keep it simple and not use any calculus to explain it.