Simple math. Take into account the power demands of the speakers to achieve the desired SPL. Then the power output of your amplifier, and subtract the two. This gives you the margin that can be lost to resistance in the speaker cable, P=I^2*R. You know the power needed to drive your speakers, and you know the speaker average impedance, which gives you the amount of current by plugging in the power and approximating resistance with average impedance. Take the power margin from above, and thus current value and use the same equation to solve for resistance of the cable. Divide this resistance by the distance in feet to obtain maximum ohms per foot of cable, and go shopping!
- ...
- 774 posts total
For the gut with the Bryston 4BSST2 and 24’ long cables: You are not doing well. The Bryston 4BSST2 http://www.bryston.com/PDF/Manuals/300006[3B4B].pdf have a DF of 500. You need a 3x0 AWG! it may be expensive... You better get closer, as 8’ and use a single 0 AWG. An other option, is to used two monoblocks and a shoer (3’) of a 4 AWG cable. |
- 774 posts total